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In a straightforward Monte Carlo approach, a perturbation effect would be
evaluated by performing two independent simulations for the perturbed and
unperturbed systems. The perturbation result is then calculated by
taking the difference between these two independent simulations. In this approach, the variance
of the result increases as the perturbation becomes smaller, and hence the
differential effect becomes difficult to observe due to a very large
uncertainty [Rie86]. This can be explained by deriving the expression of the
variance of a differential effect.
Let x be a random variable with an associated distribution and an unknown
mean. We denote the function X(x1, x2, x3,...) as an estimator of the
unknown mean. The expected value of X is given by,
and the variance by,
|
V(X) = E(X - E(X))2 .
|
(34) |
X may depend on several variables and parameters. Let us assume
a small variation in
a parameter (or parameters) resulting in a different unknown mean,
which is estimated by the function X*, with
expectation value,
and variance,
|
V(X*) = E(X* - E(X*))2 .
|
(36) |
Therefore the expectation of the differential effect due to the small variation in the
parameter(s) is given by,
|
E(X - X*) = E(X) - E(X*) ,
|
(37) |
and the variance of the differential effect by,
|
V(X-X*) = V(X) + V(X*) - 2 cov(X,X*) .
|
(38) |
If the two estimates E(X) and E(X*) are obtained by two independent Monte
Carlo simulations (i.e., in the absence of any correlations between the two
simulations), the covariance term in equation (3.6) vanishes and the
variance is
|
V(X-X*) = V(X) + V(X*).
|
(39) |
This is larger than either of the variances separately and may be larger than
the expression given in equation (3.6) [Spa69]. Hence, it is possible
to reduce the variance of
the differential effect, specially for small perturbations, if one
has a strong positive correlation between the unperturbed and perturbed
Monte Carlo simulations.
Next: Numerical Examples
Up: CORRELATED SAMPLING MONTE CARLO
Previous: Introduction
Amitava Majumdar
9/20/1999